Probability and Expected Value
Nordstrom, Introduction to Game Theory §2.3 · nordstrommath.com · CC BY-SA 4.0
A mixed strategy assigns probabilities to pure strategies. The expected value is the weighted average payoff: multiply each outcome by its probability and sum. A game is fair when the expected value is zero.
Probability over strategies
When a player randomizes, each pure strategy gets a probability. The probabilities must sum to 1. A probability distribution over strategies is the simplest object in mixed-strategy game theory. The same machinery applies to
one-shot bidding, where a bidder chooses a bid under uncertainty about the competition.
Expected value
The expected value of a game is what you'd average per play over many repetitions. Multiply each outcome's payoff by its probability, then sum. If the expected value is zero, the game is fair. If it's negative, the house wins on average.
Expected value of a mixed strategy
When both players mix, the expected payoff is the weighted average over all strategy combinations. Each cell of the payoff matrix contributes its payoff times the product of both players' probabilities for that cell.
Notation reference
| Symbol | Scheme | Meaning |
|---|---|---|
| P(E) | p | Probability of event E, between 0 and 1 |
| E(X) | (expected-value ...) | Expected value: weighted average payoff |
| sigma | (make-mixed-strategy ...) | Mixed strategy: probability distribution over actions |
| E(X) = 0 | (= ev 0) | Fair game: neither player has an edge |
Neighbors
Nordstrom series
- 🍞 §2.2 Dominated Strategies — previous section
- 🍞 §2.4 Equilibrium Points — next section
- 🍞 §3.1 Repeated Games — where mixed strategies pay off
Foundations (Wikipedia)